Question

Равномерно поднимает груз весом 100 Г С помощью подвижного блока, рабочий прикладывает силу 70 Н. Каков КПД этого блока?

Answer 1

В подвижном блоке требуемая сила ДОЛЖНА быть меньше в 2 раза (но это без учета силы трения) . и длина больше в два раза. l2=2l1
A полезная=F1*l1=100*l1

A затраченная=F2*l1=70*2l1=140l1

КПД=Aполезная/А затраченная = 100*l1/140l1=10/14=5/7
Как написано выше - это примерно 71,4%

Answer 2

Calculation of Efficiency (КПД) of the Block

To calculate the efficiency (КПД) of the block, we need to determine the work input and the work output.

The work input (W_input) is given by the formula:

W_input = Force × Distance

In this case, the force applied by the worker is 70 N, and the distance over which the force is applied is not provided in the question. Therefore, we cannot calculate the work input without this information.

The work output (W_output) is given by the formula:

W_output = Force × Distance

In this case, the force applied by the block is equal to the weight of the load, which is 100 N. The distance over which the force is applied is also not provided in the question. Therefore, we cannot calculate the work output without this information.

Without the values for the distance over which the forces are applied, we cannot calculate the efficiency (КПД) of the block.

Please provide the distance over which the forces are applied so that we can calculate the efficiency (КПД) of the block accurately.