Question

В электрическом чайнике 2 л. воды, начальная температура которой 15 граудсов, закипают через 10 мин. Напряжение сети 220 В. Чему равна сила тока в нагревательном элементе чайника? Потери энергии не учитывайте.

Answer 1

Дано:
m=2кг
t2=100℃
t1=15℃
U=220B
t=600c
c=4200 Дж/кг℃
L=2,3*10^6 Дж/кг
Найти:
I-?
Решение:
Q1+Q3=Q2
Q1=cm(t2-t1)=4200*2*85=714000Дж
Q3=Lm=2300000*3=6900000Дж
Q2=A
A=IUt
I=Q1+Q3/Ut=7614000/220*600=57,7А

Ответ: 57,7А

Answer 2

Calculation of Current in the Heating Element of the Electric Kettle

To calculate the current in the heating element of the electric kettle, we can use Ohm's Law, which states that the current (I) flowing through a conductor is equal to the voltage (V) across the conductor divided by the resistance (R) of the conductor. In this case, the heating element of the electric kettle acts as the conductor.

Given: - Initial temperature of water (T1) = 15 degrees Celsius - Final temperature of water (T2) = boiling point (100 degrees Celsius) - Time taken for water to boil (t) = 10 minutes = 600 seconds - Voltage of the power supply (V) = 220 volts

We need to find the current (I) flowing through the heating element.

To calculate the resistance (R) of the heating element, we can use the formula:

R = (T2 - T1) / (V * t)

Substituting the given values:

R = (100 - 15) / (220 * 600)

Calculating the resistance:

R = 0.00625 ohms

Now, we can calculate the current (I) using Ohm's Law:

I = V / R

Substituting the values:

I = 220 / 0.00625

Calculating the current:

I ≈ 35200 amperes

Therefore, the current flowing through the heating element of the electric kettle is approximately 35200 amperes.

Please note that this calculation assumes ideal conditions and does not take into account any energy losses.