Question

Кое количество теплоты теряет вода в пруду при охлождении на 5 градусов? Площадь пруда равна 420 м, глубина равна 1,4 м

Answer 1

Дано
S=420 м²
h=1.4 м
р=1000 кг/м³
с=4200 Дж/кгград
Δt=-5 C
Q-?
m=S*h*p   m=420*1.4*1000=588 000 кг
Q=mcΔt   Q=588000*4200*(-5)=123 480*10^4 Дж Q≈1234,8 МДж

Answer 2

Calculation of Heat Loss in a Pond

To calculate the amount of heat lost by water in a pond when it cools by 5 degrees Celsius, we need to consider the specific heat capacity of water and the volume of the pond.

Given information: - Area of the pond: 420 m² - Depth of the pond: 1.4 m

To calculate the volume of the pond, we multiply the area by the depth: Volume = Area × Depth = 420 m² × 1.4 m = 588 m³

The specific heat capacity of water is approximately 4.18 J/g°C.

To calculate the heat lost, we need to convert the volume of water in the pond from cubic meters to grams. Since the density of water is approximately 1 g/cm³, we can assume that 1 m³ of water is equal to 1000 kg or 1,000,000 g.

Therefore, the mass of water in the pond is: Mass = Volume × Density = 588 m³ × 1,000,000 g/m³ = 588,000,000 g

Now, we can calculate the heat lost using the formula: Heat Lost = Mass × Specific Heat Capacity × Temperature Change

Given: Temperature Change = 5°C Specific Heat Capacity = 4.18 J/g°C Mass = 588,000,000 g

Heat Lost = 588,000,000 g × 4.18 J/g°C × 5°C = 12,285,600,000 J

Therefore, the amount of heat lost by the water in the pond when it cools by 5 degrees Celsius is approximately 12,285,600,000 Joules.

Please note that this calculation assumes that there are no other factors affecting the heat loss, such as wind or insulation.