Question

ящик с деталями весит 500Н. какая сила требуется для равномерного перемещения этого ящика по горизонтальному полу, если сила трения составляет 0,05 веса ящика с деталями.

Answer 1

P = 500 H
F = Fтр = kP =0.05*500 =25 H

Answer 2

Calculating the Force Required to Move the Box

To calculate the force required to move the box with a weight of 500N and a coefficient of friction of 0.05, we can use the formula:

Force of Friction (Ff) = Coefficient of Friction (μ) × Normal Force (N)

Where: - Coefficient of Friction (μ) = 0.05 (given) - Normal Force (N) = Weight of the box = 500N (given)

Now, let's calculate the force of friction using the given values:

Ff = 0.05 × 500N Ff = 25N

So, the force of friction acting on the box is 25N.

Force Required for Uniform Motion

To move the box with uniform motion on a horizontal surface, the force applied must overcome the force of friction. The force required to move the box with uniform motion can be calculated using the formula:

Force Required (F) = Force of Friction (Ff)

Substituting the value of force of friction:

F = 25N

Therefore, the force required to move the box with uniform motion on a horizontal surface, considering a force of friction of 25N, is 25N.