Question

Брусок массой 900г соскальзывает с доски, наклоненной к горизонту под углом 30 градусов с ускорением 1,3 м/с2. Каков вес бруска? Как он направлен? Примите ℊ=9,8 м/с.

Answer 1

Р=m×9,8=0,9кг×9,8(посчитай)
вес направлен всегда к центру земли

Answer 2

Calculating the Weight and Direction of the Block

To calculate the weight and direction of the block, we can use the given information about the block's mass, the angle of the incline, and the acceleration due to gravity.

Given: - Mass of the block (m): 900g - Angle of the incline (θ): 30 degrees - Acceleration (a): 1.3 m/s^2 - Acceleration due to gravity (g): 9.8 m/s^2

Calculating the Weight of the Block

The weight of the block can be calculated using the formula: \[ W = m \times g \]

Where: - \( W \) = Weight of the block - \( m \) = Mass of the block - \( g \) = Acceleration due to gravity

Substituting the given values: \[ W = 0.9kg \times 9.8 m/s^2 \]

\[ W = 8.82N \]

The weight of the block is 8.82N.

Determining the Direction of the Block

The direction of the block can be determined by analyzing the forces acting on it. Since the block is sliding down the incline, the direction of its acceleration will be along the incline.

Therefore, the block's direction of motion is along the incline.

In summary, the weight of the block is 8.82N, and its direction of motion is along the incline.