Question

В идеальном колебательной контуре амплитуда колебаний силы тока в катушке индуктивности равна 10 мА , а амплитуда колебаний заряда конденсатора равна 5 нКл . в момент времени t заряд конденсатора равен 3 нКл . найдите силу тока в катушке в этот момент

Answer 1

3*10^-9=5*10^-9*sin(wt)

i=10^-2*cos(wt)

sin(wt)=0.6

cos(wt)=0.4

I=10^-2*0.4=4 мА

Answer 2

Calculation of Current in the Inductor

To find the current in the inductor at a given time, we can use the relationship between the charge on the capacitor and the current in the inductor in an ideal oscillatory circuit.

Given: - Amplitude of current in the inductor (I_L) = 10 mA - Amplitude of charge on the capacitor (Q) = 5 nC - Charge on the capacitor at time t = 3 nC

We can use the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage across the capacitor.

Let's assume the capacitance of the capacitor is C farads. Then, the voltage across the capacitor at any time t is given by V = (1/C) * Q.

Now, let's find the current in the inductor at the given time.

Solution:

1. Calculate the voltage across the capacitor at time t: - V = (1/C) * Q

2. Calculate the current in the inductor at time t: - I_L = V / X_L, where X_L is the inductive reactance.

To calculate the inductive reactance, we can use the formula X_L = 2πfL, where f is the frequency and L is the inductance.

Since the problem does not provide the frequency or inductance, we cannot calculate the inductive reactance accurately. Therefore, we cannot determine the current in the inductor at the given time without additional information.

Please provide the frequency or inductance to proceed with the calculation.