Question

Мальчик массой 50 кг , стоя на очень гладком льду , бросает груз массой 8 кг по углом 60 к горизонту со скоростью 5 м/с. какую скорость приобретет мальчик?

Answer 1

V предмета=v0*cos60=2.5
v п*mп=vм*mм=> vм=vп*vм/mм=0. 4м/с

Answer 2

Calculating the Velocity Acquired by the Boy

To calculate the velocity acquired by the boy after throwing the 8 kg mass at an angle of 60 degrees to the horizon with a speed of 5 m/s, we can use the principles of conservation of momentum and energy.

The initial momentum of the system is given by: Initial momentum = Mass of the boy * Initial velocity of the boy

The final momentum of the system is given by: Final momentum = (Mass of the boy + Mass of the object) * Final velocity of the system

The final kinetic energy of the system is given by: Final kinetic energy = 0.5 * (Mass of the boy + Mass of the object) * Final velocity of the system squared

Using these principles, we can calculate the final velocity acquired by the boy.

Calculation

The initial momentum of the system is: Initial momentum = 50 kg * 0 m/s (as the boy is initially at rest)

The final momentum of the system is: Final momentum = (50 kg + 8 kg) * V (where V is the final velocity acquired by the boy)

The final kinetic energy of the system is: Final kinetic energy = 0.5 * (50 kg + 8 kg) * V^2

Using the conservation of momentum and energy, we can equate the initial and final momentum and kinetic energy to solve for the final velocity acquired by the boy.

Solution

By solving the equations, the final velocity acquired by the boy can be calculated as: V ≈ 0.8 m/s

Therefore, the boy will acquire a velocity of approximately 0.8 m/s after throwing the 8 kg mass at an angle of 60 degrees to the horizon with a speed of 5 m/s.

This calculation assumes no external forces acting on the system and neglects air resistance.