Question

помогите решить задачу. Мальчик вышел из дому и прошел по прямым улицам сначала 2 квартала к востоку, а затем 2 квартала к северу (длина квартала 150м). Определить путь и перемещение.

Answer 1

путь=2*2*150=600 м

перемещенее из теоремы пефагора=корень из(300²+300²)=корень из 180000=424,26 м

Answer 2

Путь мальчика S = 4 квартала = 4*150 = 600м

Перемещение определим по теореме Пифагора  

L = √(2²+2²) = √8 = 2√2 квартала = 300√2 м ≈ 424 м

Answer 3

Task Analysis

The boy's movement can be analyzed in terms of the distance traveled and the displacement from his starting point.

Distance Traveled

The boy first walks 2 blocks to the east and then 2 blocks to the north. Each block has a length of 150 meters.

Calculating the Distance Traveled

To find the total distance traveled, we can use the formula: Total Distance = Distance to the East + Distance to the North

Solution

Using the given information, we can calculate the total distance traveled by the boy.

The total distance traveled is: Total Distance = (2 blocks to the east * 150 meters/block) + (2 blocks to the north * 150 meters/block)

Total Distance = (2 * 150) + (2 * 150) = 300 + 300 = 600 meters

Therefore, the boy traveled a total distance of 600 meters.

Displacement

The displacement is the straight-line distance from the initial point to the final point.

Calculating the Displacement

To find the displacement, we can use the Pythagorean theorem: Displacement = √(Distance to the East^2 + Distance to the North^2)

Solution

Using the given information, we can calculate the displacement of the boy.

The displacement is: Displacement = √((2 blocks to the east * 150 meters/block)^2 + (2 blocks to the north * 150 meters/block)^2)

Displacement = √((2 * 150)^2 + (2 * 150)^2) = √(90000 + 90000) = √180000 = 424.26 meters

Therefore, the displacement of the boy is approximately 424.26 meters.

Conclusion

The boy traveled a total distance of 600 meters and had a displacement of approximately 424.26 meters from his starting point.