Question

В баллоне вместимостью 1.66 м ^3 находится азот массой 2 кг при давлении 100 кПа. Чему равна температура этого газа? Молярная масса азота 0,028 кг/моль.

Answer 1

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Answer 2

Calculating the Temperature of Nitrogen Gas

To calculate the temperature of the nitrogen gas in the given scenario, we can use the ideal gas law equation:

PV = nRT

Where: - P = pressure (in pascals) - V = volume (in cubic meters) - n = number of moles of gas - R = ideal gas constant (8.314 J/(mol·K)) - T = temperature (in kelvin)

Given: - Volume (V) = 1.66 m^3 - Mass of nitrogen (m) = 2 kg - Pressure (P) = 100 kPa - Molar mass of nitrogen (M) = 0.028 kg/mol

First, we need to calculate the number of moles of nitrogen gas using the mass and molar mass:

n = m / M

n = 2 kg / 0.028 kg/mol

n ≈ 71.43 mol

Now, we can rearrange the ideal gas law equation to solve for temperature (T):

T = (P * V) / (n * R)

Substitute the given values:

T = (100,000 Pa * 1.66 m^3) / (71.43 mol * 8.314 J/(mol·K))

Let's calculate the temperature.