Question

Манганиновая проволока длинной 8 м и площадью сечения 0,8мм*2 включена в цепь с аккумулятором . Сила тока в цепи 0,3 А . Определите напряжение . ( удельное сопротивление 0, 43 Ом*мм/м

Answer 1

U=I*R
R= p*l/S=8*0,43/0,8=4,3 ОМ
U=0,3*4,3=1,29В

Answer 2

Calculation of Voltage in the Circuit

To determine the voltage in the circuit, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R). In this case, the resistance is given by the specific resistance (ρ) multiplied by the length (L) divided by the cross-sectional area (A) of the wire.

Given: - Length of the wire (L) = 8 m - Cross-sectional area of the wire (A) = 0.8 mm^2 - Current in the circuit (I) = 0.3 A - Specific resistance (ρ) = 0.43 Ω*mm/m

Using the formula for resistance (R = ρ * L / A), we can calculate the resistance of the wire: R = (0.43 Ω*mm/m * 8 m) / (0.8 mm^2) R = 4.3 Ω

Now, we can calculate the voltage (U) using Ohm's Law: U = I * R U = 0.3 A * 4.3 Ω U ≈ 1.29 V

Therefore, the voltage in the circuit is approximately 1.29 V.