
Какую скорость развивает моторная лодка пройдя из состояния покоя 800 м с ускорением 4м/с?


Ответы на вопрос

2as=V²-V0²
V=√(2as+V0²)
V0=0 =>
V=√2as
V=√2*4м/с²*800м
V=80м/с



Motorboat Speed Calculation
To calculate the speed of a motorboat that has traveled a distance of 800 m from rest with an acceleration of 4 m/s², we can use the following kinematic equation:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t))
First, we need to find the final velocity (v) using the given values: - Initial velocity (u) = 0 m/s (as the boat starts from rest) - Distance (s) = 800 m - Acceleration (a) = 4 m/s²
We can use the following equation to find the time (t) it takes for the boat to reach this distance: Distance (s) = Initial velocity (u) * Time (t) + (0.5 * Acceleration (a) * Time (t)²)
Let's calculate the final velocity (v) and the time (t) using the given values.
Calculation
Using the equation Distance (s) = Initial velocity (u) * Time (t) + (0.5 * Acceleration (a) * Time (t)²), we can solve for time (t): 800 = 0 * t + (0.5 * 4 * t²)This simplifies to: 800 = 2t²
Solving for t: t² = 400 t ≈ 20 seconds
Now that we have the time (t), we can calculate the final velocity (v) using the equation Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)): v = 0 + (4 * 20) v = 80 m/s
Answer
The motorboat reaches a speed of 80 m/s after traveling a distance of 800 m from rest with an acceleration of 4 m/s².This calculation is based on the kinematic equations of motion and the given values.


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