Question

Для нагревания 400г свинца от 25 до 45градусов цельсия,требуется количество теплоты 1120 ДЖ.Опредилите удельную теплоемкость

Answer 1

Дано:
Δt = 45 C - 25 C = 20 C;
m = 400 г = 0.4 кг;
Q = 1120 Дж
Найти:
q - ?
Решение:
q = Q / (m * Δt) = 1120 Дж / (0.4 кг * 20 С) = 140 Дж/кг*С
Ответ: 140 Дж/кг*С

Answer 2

Calculating Specific Heat Capacity

To calculate the specific heat capacity (C) of the lead, we can use the formula:

Q = mcΔT

Where: - Q = amount of heat energy (in joules) - m = mass (in kilograms) - c = specific heat capacity (in joules per kilogram per degree Celsius) - ΔT = change in temperature (in degrees Celsius)

Given: - Q = 1120 J - m = 400 g = 0.4 kg - ΔT = 45°C - 25°C = 20°C

We can rearrange the formula to solve for specific heat capacity (c):

c = Q / (mΔT)

Substitute the given values:

c = 1120 J / (0.4 kg * 20°C)

c = 1120 J / 8 kg°C

c = 140 J/kg°C

So, the specific heat capacity of lead is 140 J/kg°C.