Question

Шар после удара прокатился по земле 32 м. Какой скоростью обладал шар сразу же после удара, если коэффициент трения равен 0,1?

Answer 1

µ = V^2/2Sg-основная формула;

g =10 м/с^2 - ускорение свободного падения. 

Отсюда выразим V^2=0,1*2* 32м**10м/c^2=64м/c

Ответ:V=8м/c. 

Answer 2

Calculation of the Speed of the Ball after the Impact

To calculate the speed of the ball immediately after the impact, we can use the principle of conservation of mechanical energy. The initial kinetic energy of the ball is equal to the final kinetic energy plus the work done against friction.

The formula for the kinetic energy of an object is given by:

KE = (1/2)mv^2

Where: - KE is the kinetic energy - m is the mass of the object - v is the velocity of the object

The work done against friction can be calculated using the formula:

W = μmgd

Where: - W is the work done against friction - μ is the coefficient of friction - m is the mass of the object - g is the acceleration due to gravity - d is the distance over which the ball rolls

Since the ball rolls without slipping, the distance over which the ball rolls is equal to the distance traveled by the ball, which is given as 32 meters.

Now, let's calculate the speed of the ball immediately after the impact.

Calculation:

Given: - Distance traveled by the ball (d) = 32 meters - Coefficient of friction (μ) = 0.1

We need to know the mass of the ball to calculate its speed. Unfortunately, the mass of the ball is not provided in the question. Could you please provide the mass of the ball?