Question

Цепь состоит из двух параллельно соединенных резисторов с сопротивлениями R1=10 Oм и R2=8 Ом . Чему равна сила тока во втором резисторе,если в первом она равна 4 А? помогите пож :с

Answer 1

В параллельных резисторах токи одинаковые

Answer 2

Calculation of Current in the Second Resistor

To find the current in the second resistor, we can use Ohm's Law, which states that the current flowing through a conductor is directly proportional to the voltage across it and inversely proportional to its resistance.

Given: - Resistance of the first resistor (R1) = 10 Ω - Resistance of the second resistor (R2) = 8 Ω - Current in the first resistor (I1) = 4 A

We can use the formula: I = V/R, where I is the current, V is the voltage, and R is the resistance.

Since the two resistors are connected in parallel, the voltage across both resistors is the same. Therefore, the voltage across the first resistor (V1) is equal to the voltage across the second resistor (V2).

To find the voltage across the first resistor, we can use Ohm's Law: V1 = I1 * R1.

Substituting the given values: V1 = 4 A * 10 Ω = 40 V

Since the voltage across both resistors is the same, the voltage across the second resistor is also 40 V.

Now, we can find the current in the second resistor (I2) using Ohm's Law: I2 = V2 / R2.

Substituting the values: I2 = 40 V / 8 Ω = 5 A

Therefore, the current in the second resistor is 5 A.