Question

Частота обертання повітряного гвинта літака 1500 об/хв. Скільки обертів здійснить гвинт на шляху 90 км при швидкості польоту 180 км/год?

Answer 1

Лететь он будет пол часа так как 90/180 равно 0.5 а значить это 30 мин затем 30м*1500 = 45000

Answer 2

Calculation of the Number of Revolutions of the Airplane Propeller

To calculate the number of revolutions the airplane propeller will make on a 90 km journey at a flight speed of 180 km/h, we need to consider the relationship between distance, speed, and time.

The formula to calculate the number of revolutions is:

Number of Revolutions = (Distance / Speed) * 60

Let's plug in the given values:

Distance = 90 km Speed = 180 km/h

Using the formula, we can calculate the number of revolutions:

Number of Revolutions = (90 / 180) * 60

Number of Revolutions = 0.5 * 60

Number of Revolutions = 30 revolutions

Therefore, the propeller will make 30 revolutions on a 90 km journey at a flight speed of 180 km/h.

Please note that this calculation assumes a constant speed throughout the journey and does not take into account any other factors that may affect the actual number of revolutions.