Question

сопротивление волоска лампы накаливания 50 Ом,сопротивление проводящих проводов 0,4 Ом. Определить падение напряжения на лампе накаливания и потерю напряжения в проводящих проводах,еслии по ним проходит ток 2 А.

Answer 1

Падение напряжения на лампе U=I*R=2*50=2*50= 100 Вольт
потеря напряжения в проводах U=I*R=2*0.4=0.8 Вольт


если ответ лучший отметь.

Answer 2

Calculation of Voltage Drop in Incandescent Lamp and Loss in Conducting Wires

To determine the voltage drop across the incandescent lamp and the loss in the conducting wires, we need to use Ohm's Law, which states that the voltage drop (V) across a component is equal to the product of the current (I) flowing through it and the resistance (R) of the component.

Given: - Resistance of the incandescent lamp (R_lamp) = 50 Ω - Resistance of the conducting wires (R_wires) = 0.4 Ω - Current flowing through the wires (I) = 2 A

Voltage Drop across the Incandescent Lamp

To calculate the voltage drop across the incandescent lamp, we can use Ohm's Law:

V_lamp = I * R_lamp

Substituting the given values:

V_lamp = 2 A * 50 Ω = 100 V

Therefore, the voltage drop across the incandescent lamp is 100 volts.

Loss in the Conducting Wires

To calculate the loss in the conducting wires, we can use Ohm's Law:

V_wires = I * R_wires

Substituting the given values:

V_wires = 2 A * 0.4 Ω = 0.8 V

Therefore, the loss in the conducting wires is 0.8 volts.

Summary

- The voltage drop across the incandescent lamp is 100 volts. - The loss in the conducting wires is 0.8 volts.

Please note that these calculations assume ideal conditions and do not take into account factors such as temperature effects or variations in resistance.