Question

По наклонной плоскости высотой 1 метр было равномерно поднято тело массой 50 кг при эом затраченная работа составила 700 джоулей .КПД наклонной плоскости равен...

Answer 1

КПД=Аполезн/Азатрач=mgh/A=500/700=5/7~71%

Answer 2

Calculation of Efficiency (КПД) of the Inclined Plane

To calculate the efficiency (КПД) of the inclined plane, we need to know the work done and the energy input. In this case, the work done is given as 700 joules.

The formula for efficiency is:

Efficiency (КПД) = (Work output / Energy input) * 100%

In this case, the work output is the work done to lift the body up the inclined plane, and the energy input is the energy expended to do the work.

Since the body is lifted up a 1-meter high inclined plane, the work output can be calculated using the formula:

Work output = Force * Distance

The force can be calculated using the formula:

Force = Mass * Acceleration due to gravity

Given that the mass of the body is 50 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the force.

Let's calculate the force first:

Force = 50 kg * 9.8 m/s^2 = 490 N

Now, let's calculate the work output:

Work output = Force * Distance = 490 N * 1 m = 490 J

Now, we can calculate the efficiency:

Efficiency (КПД) = (Work output / Energy input) * 100% = (490 J / 700 J) * 100% ≈ 70%

Therefore, the efficiency (КПД) of the inclined plane is approximately 70%.

Please note that the sources provided do not directly address the specific question. However, the calculations and formulas used are based on well-established principles of physics.