Question

Определите скорость самолёта при горизонтальном полёте,если ЭДС индукции,возникающая на его крыльях длиной 15 м равна 0,12 В, а вертикальная составляющая магнитной индукции магнитного поля Земли равна 0,5*10-4 Тл.

Answer 1

$E=lBv\sin \alpha \\\ v= \frac{E}{lB\sin \alpha } \\\ v= \frac{0.12}{15\cdot0.5\cdot10^{-4}\sin90}= 160(m/c)$
Ответ: 160м/с

Answer 2

Calculation of the Speed of the Plane

To determine the speed of the plane during horizontal flight, we can use the formula for electromotive force (EMF) induced in the wings of the plane. The EMF induced is given by the equation:

EMF = B * L * v

Where: - EMF is the electromotive force induced (0.12 V in this case) - B is the vertical component of the magnetic induction of the Earth's magnetic field (0.5 * 10^-4 T in this case) - L is the length of the wings (15 m in this case) - v is the velocity of the plane

To find the velocity of the plane, we rearrange the equation as follows:

v = EMF / (B * L)

Substituting the given values, we have:

v = 0.12 V / (0.5 * 10^-4 T * 15 m)

Now, let's calculate the value of v.