Question

10.57. в каждом цикле идеальной тепловой машины к рабочему телу подводится тепло 1.0 кДж и совершается работа 300 Дж. Определите температуру нагревателя, если температура холодильника 280 К. ( 400 К )

Answer 1

Решение во вложении..!

Answer 2

Найдем КПД(n)

n=A/Q=300/1000=0,3*100%=30%

Теперь найдем тепературу нагревателя(T1)

n=1-T2/T1

0,3-1=-280/T1

0,7=280/T1

T1=280/0,7=400 К

 

Ответ: 400 К

Answer 3

Calculation of the Temperature of the Heat Source

To determine the temperature of the heat source in an ideal heat engine cycle, we can use the first law of thermodynamics, which states that the net heat transfer to the working substance is equal to the net work done by the substance.

In this case, we are given that the heat transfer to the working substance is 1.0 kJ (kilojoules) and the work done by the substance is 300 J (joules). We are also given the temperature of the cold reservoir, which is 280 K (Kelvin).

To find the temperature of the heat source, we can use the following equation:

Qh - Qc = W

Where: - Qh is the heat transfer to the working substance (1.0 kJ) - Qc is the heat transfer from the working substance to the cold reservoir (unknown) - W is the work done by the working substance (300 J)

Let's solve for Qc:

Qc = Qh - W

Substituting the given values:

Qc = 1.0 kJ - 300 J

To perform the calculation, we need to convert the units to a common one. Let's convert 1.0 kJ to joules:

1.0 kJ = 1000 J

Now we can substitute the values and calculate Qc:

Qc = 1000 J - 300 J = 700 J

Therefore, the heat transfer from the working substance to the cold reservoir is 700 J.

Now, we can use the equation for heat transfer in a heat engine cycle:

Qh / Qc = Th / Tc

Where: - Th is the temperature of the heat source (unknown) - Tc is the temperature of the cold reservoir (280 K)

Substituting the known values:

1.0 kJ / 700 J = Th / 280 K

To solve for Th, we can cross-multiply and rearrange the equation:

Th = (1.0 kJ / 700 J) * 280 K

Let's perform the calculation:

Th = (1.0 * 10^3 J / 700 J) * 280 K

Th ≈ 400 K

Therefore, the temperature of the heat source is approximately 400 K.

Please note that the calculations provided here are based on the information given in the question.