Question

Мотоциклист на повороте радиусом 25 м наклоняется под углом 45.. Какова его скорость?

Answer 1

100км/ч,посмотрел в интеренете

Answer 2

Calculation of the Motorcycle's Speed

To calculate the speed of the motorcyclist on a turn with a radius of 25 m and a tilt angle of 45 degrees, we can use the centripetal force equation:

F_c = m * a_c

where: - F_c is the centripetal force - m is the mass of the motorcyclist - a_c is the centripetal acceleration

The centripetal force can be expressed as:

F_c = m * g * tan(θ)

where: - g is the acceleration due to gravity (approximately 9.8 m/s^2) - θ is the tilt angle of the motorcyclist (45 degrees)

The centripetal acceleration can be calculated using the formula:

a_c = v^2 / r

where: - v is the velocity of the motorcyclist - r is the radius of the turn (25 m)

By substituting the expressions for centripetal force and centripetal acceleration into the initial equation, we get:

m * g * tan(θ) = m * v^2 / r

Simplifying the equation, we find:

v = sqrt(g * r * tan(θ))

Now, let's substitute the given values into the equation and calculate the speed.

Using the acceleration due to gravity g = 9.8 m/s^2, the radius of the turn r = 25 m, and the tilt angle θ = 45 degrees, we can calculate the speed v.

v = sqrt(9.8 * 25 * tan(45))

Calculating the expression, we find:

v ≈ 15.7 m/s

Therefore, the speed of the motorcyclist on the turn is approximately 15.7 m/s.

Please note that the above calculation assumes ideal conditions and does not take into account factors such as friction, air resistance, or the specific mass of the motorcyclist.