Question

Напруга в колі змінного струму змінюється за законом u=310sin100пt. 1)На яку мінімальну напругу потрібно розраховувати вимірювальні прилади?2) Якими будуть показання вольтметра при приєднанні до джерела струму?

Answer 1

2) прибор покажет 310/корень(2)= 219,2031 ~ 220 В
1) измеряемая величина не должна превышать 2/3 диапазона прибора.
в связи с этим диапазон прибора 220 * 3/2=330 В

Answer 2

Voltage in an AC Circuit

In an AC circuit, the voltage varies according to a sinusoidal law. The given equation for voltage is u = 310sin(100πt), where u represents the voltage, t represents time, and π is a mathematical constant approximately equal to 3.14159.

1) Minimum Voltage for Measuring Instruments To determine the minimum voltage required for measuring instruments, we need to consider the peak value of the voltage waveform. In this case, the peak value can be calculated by taking the absolute value of the coefficient of the sine function, which is 310. Therefore, the minimum voltage required for measuring instruments is 310 volts.

2) Voltmeter Readings When a voltmeter is connected to a source of current, it measures the effective value of the voltage, also known as the root mean square (RMS) value. The RMS value of a sinusoidal waveform is equal to the peak value divided by the square root of 2.

For the given equation, the peak value is 310 volts. Therefore, the RMS value can be calculated as follows:

RMS value = Peak value / √2 = 310 / √2 ≈ 219.7 volts.

Hence, the voltmeter will show a reading of approximately 219.7 volts when connected to the source of current.

Please note that the above calculations are based on the given equation and assumptions about the nature of the AC circuit. If there are any additional details or specific conditions, please provide them for a more accurate response.