Question

Тележка массой 3 кг движущаяся со скоростью 2м/с2 сталкивается с неподвижной тележкой массой 5 кг и сцепляется с ней. Чему равен импульс обеих тележек после взаимодействия ?????

Answer 1

M-=3 кг
v1-=4 м/с
v2-скорость облеих тележек после столкновения.
СИ: m×v1=(m+m)×v2
v2=m×v1/(m+m)=12/6=2
импульс тележек после взаимодействия=(m+m)×v2=(3+3)2=12
Ответ:импульс=12

Answer 2

Calculation of the impulse of both carts after the interaction

To calculate the impulse of both carts after the interaction, we need to use the principle of conservation of momentum. According to this principle, the total momentum before the interaction is equal to the total momentum after the interaction.

The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) is defined as:

p = m * v

where: - p is the momentum, - m is the mass of the object, and - v is the velocity of the object.

Let's calculate the momentum of each cart before the interaction:

For the first cart (mass = 3 kg, velocity = 2 m/s): p1 = m1 * v1 = 3 kg * 2 m/s = 6 kg m/s For the second cart (mass = 5 kg, velocity = 0 m/s since it is stationary): p2 = m2 * v2 = 5 kg * 0 m/s = 0 kg m/s

Since the second cart is stationary, its momentum is zero.

According to the principle of conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction. Therefore, the total momentum after the interaction will be the same as the momentum of the first cart before the interaction.

Hence, the impulse of both carts after the interaction is 6 kg m/s.