Question

Конденсатор емкостью 20 мкФ заряжен до разности потенциалов, равной 100 В. Найти энергию конденсатора.

Answer 1

ёмкость конденсатора определяется по формуле:

 

W = CU^2/2.

в си: С измеряется в Ф; в 1 Ф 10^-6 мкф => 

W=20*10^-6*100^2/2=0,2/2=0,1 Дж

Answer 2

Конденсатор емкостью 20 мкФ заряжен до разности потенциалов, равной 100 В. Найти энергию конденсатора.

C = 20 мкФ

U = 100 В.

W = CU^2/2 = 20*10^-6 *100^2/2 =  0.1 Дж

 

 

 

 

 

Answer 3

Calculation of Energy in a Capacitor

To find the energy stored in a capacitor, we can use the formula:

E = (1/2) * C * V^2

Where: - E is the energy stored in the capacitor, - C is the capacitance of the capacitor, and - V is the potential difference across the capacitor.

In this case, we are given that the capacitance of the capacitor is 20 μF and the potential difference is 100 V. Let's substitute these values into the formula to calculate the energy:

E = (1/2) * 20 μF * (100 V)^2

To simplify the calculation, we need to convert the capacitance from microfarads (μF) to farads (F). Since 1 μF is equal to 1 × 10^-6 F, the capacitance becomes:

C = 20 μF = 20 × 10^-6 F

Now, we can substitute the values into the formula and calculate the energy:

E = (1/2) * (20 × 10^-6 F) * (100 V)^2

Simplifying further:

E = (1/2) * (20 × 10^-6 F) * (100 V)^2 = 0.1 * 20 × 10^-6 F * 10000 V^2 = 0.1 * 20 × 10^-6 F * 10^6 V^2 = 2 × 10^-6 F * 10^6 V^2 = 2 J

Therefore, the energy stored in the capacitor is 2 Joules.