Question

Снежка массой 200г ударяется об стенку. Сколько снега растает, если температура окружающей среды равна нулю градусам Цельсия а вся кинетическая энергия передается снегу?

Answer 1

$W_k = Q$
Кинетическая энергия:
$W_k = 0.5mv^2$
Часть льда, которая расплавится.
$Q = m_oL$ (L - это λ, просто в формулах нет лямды)  
Тогда
$m_oL = 0.5mv^2$
$m_o = \frac{mv^2}{2L}$
Без скорости численного ответа к сожалению нет, так что имеем только формулу.

Answer 2

Calculation of the Amount of Melted Snow

To calculate the amount of snow that melts when a snowball with a mass of 200g hits a wall, we need to consider the transfer of kinetic energy from the snowball to the snow.

Given: - Mass of the snowball (m) = 200g = 0.2kg - Temperature of the surroundings (T) = 0 degrees Celsius

To determine the amount of snow that melts, we need to know the specific heat capacity of snow, which represents the amount of heat required to raise the temperature of a given mass of snow by 1 degree Celsius. Unfortunately, I couldn't find a specific value for the specific heat capacity of snow in the search results.

However, we can make some assumptions to estimate the amount of melted snow. Let's assume that the specific heat capacity of snow is similar to that of ice, which is approximately 2.09 J/g°C

To calculate the amount of melted snow, we can use the following formula:

Q = m * c * ΔT

Where: - Q is the heat transferred to the snow (in joules) - m is the mass of the snow (in kilograms) - c is the specific heat capacity of snow (in joules per gram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Since the temperature of the surroundings is 0 degrees Celsius, the change in temperature (ΔT) is also 0. Therefore, the amount of melted snow can be approximated as 0.

Please note that this is an estimation based on assumptions, and the actual amount of melted snow may vary depending on various factors such as the specific heat capacity of snow and the efficiency of energy transfer.

I hope this helps! Let me know if you have any further questions.