Question

Диск брошен под углом 45° к горизонту. Достиг высоты 15м. Найти дальность полёта диска.

Answer 1

Запишем формулы мах. высоты подъема и дальности полета,
hмах=v0^2*(sin a)^2 / 2g, L=v0^2 *sin 2a / g, разделим левые и правые части друг на друга hмах / L = v0^2*(sin a)^2*g / v0^2*2g*sin 2a, сократим на v0^2, g.
hмах / L =( sin a)^2 / 2*sin 2a . (sin a)^2 = sin a *sin a, sin 2a=2sin a*cos a ) ,подставим и сократим на sin a , ( sin a / cos a = tg a) , заменим, получим
hмах / L=tg a / 4, выразим дальность L=4*hмах / tg a ( tg 45=1).
L=4*15=60м.
L=60м.

Answer 2

Calculation of the Flight Distance of the Disc

To calculate the flight distance of the disc, we can use the information provided: the disc is thrown at an angle of 45° to the horizon and reaches a height of 15m.

To find the flight distance, we can use the following formula:

Range (R) = (v^2 * sin(2θ)) / g

Where: - R is the range or flight distance of the disc - v is the initial velocity of the disc - θ is the launch angle (45° in this case) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Let's calculate the flight distance using this formula:

Step 1: Find the initial velocity (v) of the disc.

Unfortunately, the initial velocity of the disc is not provided in the question. Without this information, it is not possible to calculate the flight distance accurately.

If you have the initial velocity of the disc, please provide it, and I will be happy to help you calculate the flight distance.