Question

Тело брошено со скоростью Vo=10 m/c под углом 45° к горизонту. Найти радиусы кривизны траектории тела в начальный момент его движения спустя время 0,5 с и в точке наивысшего подъема тела над поверхностью земли .решите плиизя

Answer 1

295° или второе 2,5 литров

Answer 2

Projectile Motion and Radius of Curvature

To find the radius of curvature of the trajectory of a projectile at the initial moment of its motion, after 0.5 seconds, and at the highest point of its motion, we can use the following steps:

1. Initial Moment of Motion: - At the initial moment, the radius of curvature can be calculated using the formula: - \( R = \frac{{(1 + y'^2)^{3/2}}}{{y"}} \) - Where \( y' \) and \( y" \) are the first and second derivatives of the trajectory equation with respect to \( x \).

2. After 0.5 Seconds: - After 0.5 seconds, we can calculate the new position of the projectile and then find the radius of curvature using the same formula as above.

3. At the Highest Point: - At the highest point, the radius of curvature can be calculated using the same formula as above.

Let's calculate the radius of curvature for each of these instances.

Initial Moment of Motion:

The initial velocity of the projectile is \( V_0 = 10 \, m/s \) at an angle of \( 45^\circ \) to the horizontal.

The radius of curvature at the initial moment can be calculated using the formula: \[ R = \frac{{(1 + y'^2)^{3/2}}}{{y"}} \]

After 0.5 Seconds:

We can calculate the new position of the projectile after 0.5 seconds and then find the radius of curvature using the same formula as above.

At the Highest Point:

At the highest point, we can calculate the radius of curvature using the same formula as above.

Let's proceed with the calculations.