Question

Сколько тепла выделиться при охлаждении олова массой 2 кг от 20 до 10 градусов

Answer 1

Все легко.

c=230 Дж/кгC'

t2=20C'

t1=10C'

Решение

Q=cm(t1-t2)

Q=230*2*(10-20)= -4600 ДЖ

Ответ:Q=-4600 ДЖ

Answer 2

Calculating Heat Release During Cooling of Lead

To calculate the heat released during the cooling of lead, we can use the formula:

Q = mcΔT

Where: - Q = heat released - m = mass of the substance - c = specific heat capacity of the substance - ΔT = change in temperature

Given: - m = 2 kg - ΔT = 20°C - 10°C = 10°C - Specific heat capacity of lead, c = 128 J/(kg·°C)

Calculation

Substitute the given values into the formula:

Q = (2 kg) * (128 J/(kg·°C)) * (10°C) Q = 2560 J

So, 2560 Joules of heat will be released during the cooling of 2 kg of lead from 20°C to 10°C.