Question

За какое время скорость автомобиля уменьшилась с 20 до 12м/с,если он двигался с ускорением равным по модулю 0,2 м/с в квадрате ?

Answer 1

 v-v0

а=-----------

      t

 

     v-v0          20-12       8

t=----------- =---------- =----- = 40 c

     a               0,2          0,2

Answer 2

Calculating the Time for the Speed to Decrease from 20 m/s to 12 m/s

To calculate the time it takes for the speed of the car to decrease from 20 m/s to 12 m/s, we can use the equation of motion under constant acceleration:

v = u + at

Where: - v = final velocity (12 m/s) - u = initial velocity (20 m/s) - a = acceleration (given as 0.2 m/s^2)

We can rearrange the equation to solve for time t:

t = (v - u) / a

Substituting the given values: t = (12 - 20) / (-0.2) t = -8 / (-0.2) t = 40 seconds

So, it takes 40 seconds for the speed of the car to decrease from 20 m/s to 12 m/s.

Therefore, the time it takes for the speed of the car to decrease from 20 m/s to 12 m/s, with an acceleration of 0.2 m/s^2, is 40 seconds.