Question

Маятник длиной 1м подвешен в кабинелифта. С какой частотой будет колебаться маятник, если лифт стартует с ускорением 1 м/с

Answer 1

Маятник длиной 1м подвешен в кабинелифта. С какой частотой будет колебаться маятник, если лифт стартует с ускорением 1 м/с

Дано    L=1 м   а=1 м/с2   T - ?   ню - ?

Если ускорение направлено вверх  T = 2*π*√L/(g+a)=6,28*√1/11=1,89 с

ν=1/T=1/1,89=0,53 Гц

Ответ  ν=0,53 Гц

Answer 2

Calculating the Frequency of the Pendulum

To calculate the frequency of the pendulum, we can use the formula:

f = 1 / (2π) * √(g / L)

Where: - f = frequency - g = acceleration due to gravity (approximately 9.81 m/s^2) - L = length of the pendulum

Given: - Length of the pendulum, L = 1m - Acceleration of the lift, a = 1 m/s^2

We can use the effective acceleration due to gravity in the lift, which is the sum of the actual acceleration due to gravity and the acceleration of the lift. The effective acceleration due to gravity, g', is given by:

g' = g + a

Substituting the values into the formula, we get:

f = 1 / (2π) * √((g + a) / L)

Let's calculate the frequency using the given values.

Calculation

Using the given values: - Length of the pendulum, L = 1m - Acceleration of the lift, a = 1 m/s^2 - Acceleration due to gravity, g ≈ 9.81 m/s^2

We can calculate the effective acceleration due to gravity, g': g' = 9.81 + 1 = 10.81 m/s^2

Now, we can calculate the frequency using the formula: f = 1 / (2π) * √(10.81 / 1) f ≈ 1.735 Hz

Conclusion

The frequency at which the pendulum will oscillate when the lift starts with an acceleration of 1 m/s^2 is approximately 1.735 Hz.