Question

Найти молярную массу Ag3(Na2O6)2 C2H7CO(OH2)4

Answer 1

Ag3(Na2O6)2=607.56
C2H7CO(OH2)4= 131.15

Answer 2

Molar mass, also known as molecular weight, is the mass of a given substance divided by the amount of substance (in moles). It is expressed in grams per mole (g/mol). To calculate the molar mass of a compound, we need to find the atomic masses of each element present in the compound and then sum them up based on their stoichiometric coefficients.

Let's calculate the molar mass of the compounds you provided:

Ag3(Na2O6)2: To calculate the molar mass of Ag3(Na2O6)2, we need to find the atomic masses of silver (Ag), sodium (Na), oxygen (O), and their respective stoichiometric coefficients.

The atomic mass of silver (Ag) is approximately 107.87 g/mol, the atomic mass of sodium (Na) is approximately 22.99 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol.

The compound Ag3(Na2O6)2 contains three silver atoms, two sodium atoms, and twelve oxygen atoms. The molar mass can be calculated as follows:

Molar mass of Ag3(Na2O6)2 = (3 * atomic mass of Ag) + (2 * atomic mass of Na) + (12 * atomic mass of O) = (3 * 107.87 g/mol) + (2 * 22.99 g/mol) + (12 * 16.00 g/mol) = 647.15 g/mol

Therefore, the molar mass of Ag3(Na2O6)2 is approximately 647.15 g/mol.

C2H7CO(OH2)4: To calculate the molar mass of C2H7CO(OH2)4, we need to find the atomic masses of carbon (C), hydrogen (H), oxygen (O), and their respective stoichiometric coefficients.

The atomic mass of carbon (C) is approximately 12.01 g/mol, the atomic mass of hydrogen (H) is approximately 1.01 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol.

The compound C2H7CO(OH2)4 contains two carbon atoms, seven hydrogen atoms, five oxygen atoms, and one water molecule (H2O) which has two hydrogen atoms and one oxygen atom. The molar mass can be calculated as follows:

Molar mass of C2H7CO(OH2)4 = (2 * atomic mass of C) + (7 * atomic mass of H) + (5 * atomic mass of O) + (2 * atomic mass of H2O) = (2 * 12.01 g/mol) + (7 * 1.01 g/mol) + (5 * 16.00 g/mol) + (2 * (2 * 1.01 g/mol + 16.00 g/mol)) = 130.22 g/mol

Therefore, the molar mass of C2H7CO(OH2)4 is approximately 130.22 g/mol.

I hope this explanation helps! Let me know if you have any further questions.