Question

на сколько градусов нагреется алюминиевая деталь массой 200 г, если ей сообщить 9200 Дж энергии? и. Воду какой массы можно нагреть от 20 до 50 градусов Цельсия, затратив для этого 2520 кДж энергии?

Answer 1

удельная теплоёмкость алюминия 930 Джоулей\кг*градус

 

масса нашей детали 0.2 кг. 

чтобы нагреть её на один градус нам надо 930\5 Джоулей энергии

930/5 = 186 Джоулей

У нас 9200 Джоулей

9200/186 = примерно 49.4 градуса

Ответ: примерно 49.4 градуса

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чтобы нагреть килограмм воды на 30 градусов, на надо затратить

4200 * 30 = 126 кДж

 

У нас есть 2520 кДж

2520/126Кдж = 20 кг воды можно нагреть

Ответ: 20кг воды

Answer 2

Calculation of Temperature Increase for an Aluminum Part

To calculate the temperature increase of an aluminum part when given a certain amount of energy, we need to use the specific heat capacity of aluminum. The specific heat capacity is the amount of heat energy required to raise the temperature of a given mass of a substance by one degree Celsius.

The specific heat capacity of aluminum is approximately 0.897 J/g°C.

Given: - Mass of the aluminum part: 200 g - Energy provided: 9200 J

To calculate the temperature increase, we can use the formula:

Q = mcΔT

Where: - Q is the energy provided (9200 J) - m is the mass of the aluminum part (200 g) - c is the specific heat capacity of aluminum (0.897 J/g°C) - ΔT is the change in temperature (unknown)

Rearranging the formula to solve for ΔT:

ΔT = Q / (mc)

Substituting the given values:

ΔT = 9200 J / (200 g * 0.897 J/g°C)

Calculating the result:

ΔT ≈ 51.39°C

Therefore, the aluminum part will increase in temperature by approximately 51.39°C when provided with 9200 J of energy.

Calculation of Water Mass for Temperature Increase

To calculate the mass of water that can be heated from 20°C to 50°C using a given amount of energy, we need to use the specific heat capacity of water. The specific heat capacity of water is approximately 4.186 J/g°C.

Given: - Initial temperature of water: 20°C - Final temperature of water: 50°C - Energy provided: 2520 kJ (2520,000 J)

To calculate the mass of water, we can use the formula:

Q = mcΔT

Where: - Q is the energy provided (2520,000 J) - m is the mass of water (unknown) - c is the specific heat capacity of water (4.186 J/g°C) - ΔT is the change in temperature (50°C - 20°C = 30°C)

Rearranging the formula to solve for m:

m = Q / (cΔT)

Substituting the given values:

m = 2520,000 J / (4.186 J/g°C * 30°C)

Calculating the result:

m ≈ 19,054.5 g

Therefore, approximately 19,054.5 grams (or 19.05 kilograms) of water can be heated from 20°C to 50°C using 2520 kJ (2520,000 J) of energy.