
Два одинаковых шарика находятся на расстоянии 18 см друг от друга и притягиваются с силой . Найти
массу каждого шарика.

Ответы на вопрос




Calculation of the Mass of Each Ball
To find the mass of each ball, we need to use the given information about the distance between the balls and the force of attraction between them.
Let's assume that the force of attraction between the balls is given by the equation:
F = G * (m1 * m2) / r^2
Where: - F is the force of attraction between the balls, - G is the gravitational constant (approximately 6.67430 × 10^-11 N m^2/kg^2), - m1 and m2 are the masses of the balls, and - r is the distance between the balls.
In this case, we know that the distance between the balls is 18 cm (or 0.18 m).
Now, we can rearrange the equation to solve for the mass of each ball:
m1 * m2 = (F * r^2) / G
Let's substitute the given values into the equation and calculate the mass of each ball.
Using the given information, we have: - Distance between the balls (r) = 18 cm = 0.18 m
Unfortunately, I couldn't find the exact value for the force of attraction between the balls in the search results. However, we can still proceed with the calculation by assuming a value for the force of attraction.
Let's assume that the force of attraction between the balls is 1 N. With this assumption, we can calculate the mass of each ball using the equation:
m1 * m2 = (F * r^2) / G
Substituting the values: - F = 1 N - r = 0.18 m - G = 6.67430 × 10^-11 N m^2/kg^2
We can now calculate the mass of each ball:
m1 * m2 = (1 * (0.18)^2) / (6.67430 × 10^-11)
Simplifying the equation: m1 * m2 = 0.018^2 / (6.67430 × 10^-11)
Calculating the value: m1 * m2 ≈ 4.860 × 10^9 kg^2
Since the masses of the two balls are the same, we can assume that m1 = m2 = m.
Therefore, we have: m^2 ≈ 4.860 × 10^9 kg^2
Taking the square root of both sides: m ≈ √(4.860 × 10^9) kg
Calculating the value: m ≈ 69,723.7 kg
So, the mass of each ball is approximately 69,723.7 kg.
Please note that the assumed value for the force of attraction between the balls may not be accurate, as I couldn't find the exact value in the search results. However, the calculation process remains the same, and you can substitute the actual value if it is available.


Топ вопросов за вчера в категории Физика
Последние заданные вопросы в категории Физика
-
Математика
-
Литература
-
Алгебра
-
Русский язык
-
Геометрия
-
Английский язык
-
Химия
-
Физика
-
Биология
-
Другие предметы
-
История
-
Обществознание
-
Окружающий мир
-
География
-
Українська мова
-
Информатика
-
Українська література
-
Қазақ тiлi
-
Экономика
-
Музыка
-
Право
-
Беларуская мова
-
Французский язык
-
Немецкий язык
-
МХК
-
ОБЖ
-
Психология
-
Физкультура и спорт
-
Астрономия
-
Кыргыз тили
-
Оʻzbek tili