Question

На сколько градусов остынет в питьевом баке емкостью 10 л кипяток,если он отдаст в окружающее пространство 2мдж теплоты?

Answer 1

Q=2 МДж= 2*10^6 Дж

V=10 л = 10*10^-3 м3

p=1000 кг/м3

с=4200 Дж/кг К

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найти ∆Т

РЕШЕНИЕ

Q=cm ∆Т=cVp ∆Т

∆Т = Q/cVp = 2*10^6 /  (4200*10*10^-3*1000)= 47.6 град

Ответ     остынет на 47.6 град

Answer 2

Calculation of Temperature Change in the Water Tank

To calculate the temperature change in the water tank, we can use the formula:

Q = mcΔT

Where: - Q = heat energy transferred (in joules) - m = mass of the substance (in kg) - c = specific heat capacity of the substance (in J/kg°C) - ΔT = change in temperature (in °C)

Given: - m = 10 kg (mass of 10 liters of water) - c = 4186 J/kg°C (specific heat capacity of water) - Q = 2,000,000 J (2 MJ)

We can rearrange the formula to solve for ΔT:

ΔT = Q / (mc)

Substitute the given values: ΔT = 2,000,000 J / (10 kg * 4186 J/kg°C)

Calculating ΔT: ΔT ≈ 47.8°C

Therefore, the temperature of the water in the tank will decrease by approximately 47.8°C when it releases 2 MJ of heat energy into the surrounding space.