Question

Мотоциклист, начав движение из состояния покоя, едет с постоянным ускорением о,8 м\с в квадрате. Какой путь он пройдет за седьмую секунду своего движения?

Answer 1

S1=at1^2/2.S2=at2^2/2.Где S1 S2 t1 t2- путь за шесть секнд и семь секунд,время шесть секунд и время семь секунд.Тогда S3=at2^2/2-at1^2/2=19.6-14.4=5.2(м).Ответ 5.2 метра

Answer 2

Calculation of the Distance Traveled by the Motorcyclist

To calculate the distance traveled by the motorcyclist in the seventh second of their motion, we need to use the equation of motion for uniformly accelerated motion:

\[s = ut + \frac{1}{2}at^2\]

Where: - s is the distance traveled - u is the initial velocity (0 m/s, as the motorcyclist starts from rest) - a is the acceleration (0.8 m/s^2) - t is the time (7 seconds)

Plugging in the values, we can calculate the distance traveled:

\[s = 0 \cdot 7 + \frac{1}{2} \cdot 0.8 \cdot 7^2\]

Simplifying the equation:

\[s = 0 + 0.5 \cdot 0.8 \cdot 49\]

\[s = 0.5 \cdot 0.8 \cdot 49\]

\[s = 0.4 \cdot 49\]

\[s = 19.6\]

Therefore, the motorcyclist will travel a distance of 19.6 meters in the seventh second of their motion.