Question

электрический кипятильник потребляет ток 4 А при напряжении 220 В. какое количество воды, нагреет этот кипятильник от 28 градусов до кипения за 10 мин

Answer 1

ДАНО                            РЕШЕНИЕ
I= 4A                            A= Q        A=U I t      Q= cm(t2-t1)
U=220 B                                m= U I t / c(t2-t1)
t1= 28
t2=100                                  m= 220*4*600 /  4200*72=1,74 кг
t= 10 мин= 600с
НАЙТИ :m

Answer 2

Calculating the Amount of Water Heated by an Electric Kettle

To calculate the amount of water that can be heated by the electric kettle, we can use the formula:

Q = m * c * ΔT

Where: - Q = amount of heat required (in joules) - m = mass of the water (in grams) - c = specific heat capacity of water (4.18 J/g°C) - ΔT = change in temperature (in °C)

Given: - Current = 4 A - Voltage = 220 V - Time = 10 min (600 seconds) - Initial temperature = 28°C - Final temperature (boiling point) = 100°C

First, let's calculate the power consumed by the electric kettle:

Calculating Power Consumption

The power consumed by the electric kettle can be calculated using the formula:

P = V * I

Where: - P = power (in watts) - V = voltage (in volts) - I = current (in amperes)

P = 220 V * 4 A P = 880 W

The power consumed by the electric kettle is 880 watts.

Calculating the Amount of Heat

The amount of heat required to heat the water can be calculated using the formula:

Q = P * t

Where: - Q = amount of heat (in joules) - P = power (in watts) - t = time (in seconds)

Q = 880 W * 600 s Q = 528000 J

The amount of heat required to heat the water is 528000 joules.

Calculating the Mass of Water

Now, let's calculate the mass of water that can be heated using the amount of heat calculated above.

Q = m * c * ΔT

Rearranging the formula to solve for mass (m):

m = Q / (c * ΔT)

m = 528000 J / (4.18 J/g°C * (100°C - 28°C)) m ≈ 528000 J / (4.18 J/g°C * 72°C) m ≈ 1984.85 g

So, the electric kettle can heat approximately 1984.85 grams of water from 28°C to boiling point (100°C) in 10 minutes.

Therefore, the electric kettle can heat approximately 1984.85 grams of water in 10 minutes.