Question

Две тележки массами 200 и 300 г движутся навстречу друг другу с одинаковыми по модулю скоростями,равными 5м\с. В результате взаимодействия они сцепились и стали двигаться вместе. С какой скоростью и в каком направлении будут двигаться тележки?

Answer 1

M1V1-m2V2=(m1+m2)•V. Т.к. V1=V2--->. V=(m1-m2)•V1 (или тут может быть не V1, а V2- без разницы) и это разделить все на m1+m2 Подставим значения: V=(300-200)•5/300+200= 1 м/с и двигаться они будут в сторону движения тележки большей массы (300г) все:)

Answer 2

Problem Analysis

Two carts with masses of 200 g and 300 g are moving towards each other with equal speeds of 5 m/s. After colliding, they become coupled and move together. We need to determine the resulting speed and direction of the carts.

Solution

The resulting speed and direction of the carts can be calculated using the conservation of momentum principle. According to this principle, the total momentum of an isolated system remains constant if no external forces act on it.

The formula for the resulting velocity after the collision is given by: \[ V = \frac{m_1 \cdot V_1}{m_1 + m_2} \]

Where: - \( m_1 \) = mass of the first cart - \( V_1 \) = velocity of the first cart - \( m_2 \) = mass of the second cart - \( V \) = resulting velocity after collision

Calculation

Using the given masses and velocities: - \( m_1 = 200 \, \text{g} = 0.2 \, \text{kg} \) - \( V_1 = 5 \, \text{m/s} \) - \( m_2 = 300 \, \text{g} = 0.3 \, \text{kg} \)

Substitute the values into the formula: \[ V = \frac{0.2 \, \text{kg} \times 5 \, \text{m/s}}{0.2 \, \text{kg} + 0.3 \, \text{kg}} \]

\[ V = \frac{1 \, \text{m/s} \times 0.2}{0.5} \]

\[ V = 0.4 \, \text{m/s} \]

Conclusion

The resulting speed of the coupled carts after the collision is 0.4 m/s. The direction of the carts after the collision will be in the same direction as their initial motion.