Question

Найдите кинетическую энергию пчёлы, имеющей массу 2 г и летящей со скоростью 15 м/с относительно Земли в системе отсчета связанной с догоняющей её другой пчелой, модуль скорости которой относительно Земли равен 5 м/с.

Answer 1

E = 0.002 * 15^2 / 2

Answer 2

Calculating the Kinetic Energy of the Bee

To calculate the kinetic energy of the bee, we can use the formula for kinetic energy:

Kinetic Energy (KE) = 0.5 * mass * velocity^2

Given: - Mass of the bee (m) = 2 g = 0.002 kg - Velocity of the bee (v) = 15 m/s - Relative velocity of the other bee (v') = 5 m/s

First, we need to find the relative velocity of the first bee with respect to the second bee. We can use the relative velocity formula:

Relative Velocity (v_rel) = Velocity of the first bee - Velocity of the second bee

v_rel = v - v'

v_rel = 15 m/s - 5 m/s = 10 m/s

Now, we can calculate the kinetic energy of the bee using the relative velocity:

KE = 0.5 * m * v_rel^2

KE = 0.5 * 0.002 kg * (10 m/s)^2

KE = 0.5 * 0.002 kg * 100 m^2/s^2

KE = 0.1 J

So, the kinetic energy of the bee, flying with a velocity of 15 m/s relative to the Earth in a frame of reference connected to the other bee, is 0.1 joules.