Question

при переходе лучей из воды в вакуум длина волны их увеличилась на 0.12 мкм.определите длины волн этих лучей в вакууме и в воде

Answer 1

L1=v/f; L=c/f; L-L1=l; v=c/n; c/f-c/(n*f)=l; f=(c*(1-1/n)l; L=l/(1-1/n)=(12*10^-8)/(1-1/1,33)=49*10^-8. Проверьте расчеты.

Answer 2

Calculating Wavelengths of Light Beams in Vacuum and Water

When light beams transition from one medium to another, such as from water to vacuum, the wavelength of the light can change. In this case, the wavelength of the light beams increased by 0.12 µm when transitioning from water to vacuum.

To determine the wavelengths of these light beams in vacuum and in water, we can use the following formula:

n₁λ₁ = n₂λ₂

Where: - n₁ and n₂ are the refractive indices of the initial and final mediums (in this case, water and vacuum). - λ₁ and λ₂ are the wavelengths of the light in the initial and final mediums.

Calculating Wavelength in Vacuum

Let's denote the wavelength of the light beam in vacuum as λ₂ and the refractive index of vacuum as n₂ (which is approximately 1).

Given that the wavelength increased by 0.12 µm, we can calculate the wavelength in vacuum using the formula:

n₁λ₁ = n₂λ₂

λ₂ = (n₁λ₁) / n₂

Substituting the values: λ₂ = (λ₁) / 1

Calculating Wavelength in Water

Now, let's denote the wavelength of the light beam in water as λ₁ and the refractive index of water as n₁.

We can calculate the wavelength in water using the same formula:

n₁λ₁ = n₂λ₂

λ₁ = (n₂λ₂) / n₁

Substituting the values: λ₁ = (1λ₂) / n₁

Conclusion

By using the given increase in wavelength and the refractive indices of water and vacuum, we can calculate the wavelengths of the light beams in vacuum and in water.