Question

При температуре 20 градусов поцельсию воздух занял объём 35л и имел давление 4атм.Каким будет давление,если температура увеличится до 40 градусов поцельсию ,и объём уменьшится в 1,5 раза? Прошу помогите,очень благодарна буду!!

Answer 1

уравнения менделеева клапейрона
p1v1/T1=P2v2/T2
p2=p1v1T2/v2T1=4aтм×35×1,5×40/20×35=12атм
Отвнт:п(2)=12атм

Answer 2

Gas Law Calculation

To calculate the new pressure of the gas when the temperature increases to 40 degrees Celsius and the volume decreases to 1.5 times the original volume, we can use the combined gas law formula:

P1V1/T1 = P2V2/T2

Where: - P1 = initial pressure - V1 = initial volume - T1 = initial temperature - P2 = final pressure (what we want to find) - V2 = final volume - T2 = final temperature

Given Values

- Initial temperature (T1) = 20 degrees Celsius = 293.15 K (Kelvin) (273.15 + 20) - Initial volume (V1) = 35 L - Initial pressure (P1) = 4 atm - Final temperature (T2) = 40 degrees Celsius = 313.15 K (273.15 + 40) - Final volume (V2) = 35 L / 1.5 = 23.33 L (35 * 1.5)

Calculation

Using the combined gas law formula:

P1V1/T1 = P2V2/T2

Substitute the given values: (4 atm * 35 L) / 293.15 K = P2 * 23.33 L / 313.15 K

Solving for P2: P2 = (4 atm * 35 L * 313.15 K) / (293.15 K * 23.33 L)

Result

After calculating, the new pressure (P2) when the temperature increases to 40 degrees Celsius and the volume decreases to 1.5 times the original volume is approximately 5.65 atm.

I hope this helps! If you have any other questions, feel free to ask.