Question

К вертикальной стене горизонтальной силой,модуль которой 20 н,прижимается брусок массой 2 кг.чтобы брусок мог скользить вниз доль стены с ускорением модуль которого 1 м/с2 при коэффициенте 0,10,к нему следует приложить вертикальную силу модуль которой

Answer 1

Очевидно что силу надо приложить не вниз а вверх как бы придерживать брусок
m*g- Fтр - Fуд= m*a
Fуд= m*g-k*N-m*a=2*10 - 0,2*20-2*1=20-4-2=14 Н
F уд  - удерживающая сила ( сила натяжения веревки) направлена вверх

Answer 2

Calculation of the Vertical Force Required

To determine the vertical force required to allow the block to slide down the wall with an acceleration of 1 m/s^2, we need to consider the forces acting on the block.

The forces acting on the block are: 1. The weight of the block, which is equal to its mass multiplied by the acceleration due to gravity (9.8 m/s^2). 2. The vertical force applied to the block, which is the force required to overcome the friction between the block and the wall.

Let's calculate the weight of the block first: Weight = mass * acceleration due to gravity Weight = 2 kg * 9.8 m/s^2 Weight = 19.6 N

Next, we need to calculate the frictional force between the block and the wall. The frictional force can be determined using the equation: Frictional force = coefficient of friction * normal force

The normal force is equal to the weight of the block, which is 19.6 N.

Now, let's calculate the frictional force: Frictional force = 0.10 * 19.6 N Frictional force = 1.96 N

To allow the block to slide down the wall with an acceleration of 1 m/s^2, the vertical force applied to the block must be equal to the sum of the weight of the block and the frictional force: Vertical force = Weight + Frictional force Vertical force = 19.6 N + 1.96 N Vertical force = 21.56 N

Therefore, to allow the block to slide down the wall with an acceleration of 1 m/s^2, a vertical force of approximately 21.56 N should be applied to the block.