Question

При сгорании топлива в тепловом двигатели за 30 мин выделилась энергия 10,8 МДж. Определите мощность двигателя , если КПД двигателя 25%

Answer 1

Я напишу с 20 процентам а вы делайте с 25. Мощность полная P=E/t=10.8 МДж/30 мин.=10800000 Дж/18 00 с = 6000 Вт                   мощность с учетом КПД P'=p * 20 %100% = 6000 Вт * 0.2 = 1200 В

Answer 2

Calculation of Engine Power

To determine the power of the engine, we can use the formula:

Power (P) = Energy (Q) / Time (t)

Given that the energy released during the combustion of fuel in the thermal engine is 10.8 MJ (megajoules) in 30 minutes, and the efficiency (η) of the engine is 25%, we can calculate the power as follows:

Energy (Q) = 10.8 MJ = 10.8 * 10^6 J

Time (t) = 30 minutes = 30 * 60 seconds = 1800 seconds

Efficiency (η) = 25% = 0.25

Using the formula for power, we can substitute the values:

Power (P) = Q * η / t = 10.8 * 10^6 * 0.25 / 1800

Calculating this expression, we find that the power of the engine is approximately 1.2 MW (megawatts).

Therefore, the power of the engine is approximately 1.2 MW.