Question

Какое количество теплоты выделится при остывании льда массой 0,5 кг от температуры - 1 до температуры - 5

Answer 1

Q=Cm(t2-t1) подставь значения и найди

Answer 2

Calculation of Heat Released during the Cooling of Ice

To calculate the amount of heat released during the cooling of ice from a temperature of -1°C to a temperature of -5°C, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat released or absorbed (in joules) - m is the mass of the substance (in kilograms) - c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

In this case, we have: - m = 0.5 kg (mass of ice) - ΔT = -5°C - (-1°C) = -4°C (change in temperature)

Now, we need to find the specific heat capacity of ice. According to the search results, the specific heat capacity of ice is not directly provided. However, we can assume it to be approximately 2100 J/kg°C based on a common value for the specific heat capacity of ice.

Using the formula, we can calculate the heat released:

Q = m * c * ΔT = 0.5 kg * 2100 J/kg°C * (-4°C) = -4200 J

Therefore, the amount of heat released during the cooling of ice from -1°C to -5°C is approximately -4200 joules. Please note that the negative sign indicates that heat is being released.