Question

Поезд, движущийся со скоростью 15 м/с, через 30 с после начала торможения остановился. Чему равен тормозной путь, если ускорение при торможении 0,5 м/с в квадрате?

Answer 1

s = v0t x at в квадрате /2

 

подставляем значения в формулу:

 

s= 15x30 + 0.5 x 30 в квадрате /2 = 450 - 0.5 x 900/2 = 450 - 225 = 225 метр

 

Ответ : тормозной путь равен 225 метр

Answer 2

Answer in detail. A train moving at a speed of 15 m/s stopped 30 s after the start of braking. What is the braking distance if the acceleration during braking is 0.5 m/s squared?

To answer this question, we need to use the formula for the displacement of a body moving with constant acceleration:

s = v0 * t + a * t^2 / 2

where s is the displacement, v0 is the initial velocity, t is the time, and a is the acceleration.

We are given the values of v0, t, and a, so we can plug them into the formula and calculate s:

s = 15 * 30 + 0.5 * 30^2 / 2 s = 450 + 225 s = 675 m

Therefore, the braking distance of the train is 675 m. This means that the train traveled 675 m from the moment it started braking until it stopped.