Question

Какое кол-во теплоты необходимо для обращения в пар 3 кг воды, если она нагрета до t кипения

Answer 1

Дано:
m=3кг
Lводы= 2 300 000Дж/кг
t=100
Найти:Q
Решение:
Qкипения воды = Q
L*m=Q
2 300 000 * 3 = Q
Q = 6 900 000Дж

Answer 2

Calculating Heat Required to Convert Water to Steam

To calculate the amount of heat required to convert 3 kg of water into steam at its boiling point, we can use the formula:

Q = m * L

Where: - Q is the heat required - m is the mass of the substance - L is the specific latent heat of vaporization for water

Given: - m = 3 kg - t = 100°C (boiling point of water) - L = 2260 kJ/kg (specific latent heat of vaporization for water)

Using the formula, we can calculate the heat required:

Q = 3 kg * 2260 kJ/kg = 6780 kJ

Therefore, the amount of heat required to convert 3 kg of water into steam at its boiling point (100°C) is 6780 kJ.

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