Question

На высоте 25 метров тело бросили вертикально вниз с начальной скоростью 10м/с. Какова скорость будет в конце падения?

Answer 1

Закон сохранения энергии
m*g*25+0.5*m*10^2=0.5*m*V^2--->[:m]
10*25+0.5*10^2=0.5*V^2
V=24.5 m/s

Answer 2

Calculation of the Final Velocity

To calculate the final velocity of an object that is dropped vertically from a height, we can use the equation:

v^2 = u^2 + 2as

Where: - v is the final velocity - u is the initial velocity (which is 10 m/s in this case, as the body is dropped vertically) - a is the acceleration due to gravity (which is approximately 9.8 m/s^2) - s is the distance traveled (which is the height of 25 meters)

Plugging in the values, we get:

v^2 = (10 m/s)^2 + 2 * 9.8 m/s^2 * 25 m

Simplifying the equation, we have:

v^2 = 100 m^2/s^2 + 490 m^2/s^2 * 25 m

v^2 = 100 m^2/s^2 + 12250 m^2/s^2

v^2 = 12350 m^2/s^2

Taking the square root of both sides to find the final velocity, we get:

v = √(12350 m^2/s^2)

Calculating the square root, we find:

v ≈ 111.11 m/s

Therefore, the final velocity at the end of the fall will be approximately 111.11 m/s.