Question

Определите веичину архимедовой силы , дейстующей на тело объемом 0,4 м3 , если оно на половинуопущено в воду

Answer 1

Дано V=0,4м3   Vв=V/2=0,2м3   Fa- ?

Fa=p*g*Vв=1000*10*0.2=2000Н

Answer 2

Calculating the Buoyant Force

To calculate the buoyant force acting on an object partially submerged in water, we can use the formula:

Buoyant force = weight of the water displaced

The weight of the water displaced can be calculated using the formula:

Weight of water displaced = density of water × volume of water displaced × acceleration due to gravity

Given: - Volume of the object submerged in water (V) = 0.4 m^3 - The object is half-submerged in water

Density of Water

The density of water is approximately 1000 kg/m^3.

Volume of Water Displaced

When the object is half-submerged, the volume of water displaced is half of the object's volume, which is 0.4 m^3 / 2 = 0.2 m^3.

Calculating the Buoyant Force

Using the provided information, we can calculate the buoyant force acting on the object:

Weight of water displaced = 1000 kg/m^3 × 0.2 m^3 × 9.81 m/s^2

By calculating the weight of the water displaced, we can determine the buoyant force acting on the object.