Question

автомобиль двигаясь со скоростью 43,2км /ч останавливаяется при тормажении в 3с. какое расстояние он пройдет до остановки?

Answer 1

S=Vt $S=v_{0}t + \frac{at^{2}}{2}$ 

Answer 2

Дано:                                  Решение:
U=43,2 км/ч                        S=U*t/2
t=3c                                     S=43,2 км/ * 3с/2=64,8 км
Найти:
s-?
Ответ:64,8 км 

Answer 3

Calculating Stopping Distance

To calculate the stopping distance of the car, we can use the formula:

Stopping distance = Initial velocity * Time + 0.5 * Acceleration * Time^2

Where: - Initial velocity = 43.2 km/h - Time = 3 s - Acceleration can be calculated using the formula: Acceleration = Change in velocity / Time

Let's calculate the stopping distance step by step.

Calculating Acceleration

First, let's convert the initial velocity from km/h to m/s: - 43.2 km/h = 43.2 * (1000 m / 3600 s) = 12 m/s

Now, we can calculate the acceleration: - Change in velocity = Initial velocity = 12 m/s - Time = 3 s

Acceleration = Change in velocity / Time = 12 m/s / 3 s = 4 m/s^2

Calculating Stopping Distance

Now, we can use the formula to calculate the stopping distance: - Stopping distance = 12 m/s * 3 s + 0.5 * 4 m/s^2 * (3 s)^2 - Stopping distance = 36 m + 0.5 * 4 m/s^2 * 9 s^2 - Stopping distance = 36 m + 18 m - Stopping distance = 54 m

Therefore, the car will travel a distance of 54 meters before coming to a complete stop.

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