Question

В кастрюлю массой 300 г и объемом 1 л налили воду.начальная температура кастрюли с водой 15 градусов.Для нагревания воды в кастрюле до кипения потребовалось 368,73кДж.Из какого материала сделана кастрюля

Answer 1

Дано:

m1 = 300 г = 0,3 кг

V = 1 л = 0,001 м^3

t1 = 15*C

t2 = 100*c

Q = 368,73 кДж = 368730 Дж

с2 = 4200 Дж/(кг*С)

_________________________

с1 - ?

 

Решение:

Q = c1m1(t2 - t1)+c2m2(t2-t1), m2 = ρ*V = 1000*0.001 = 1 кг - масса воды в кастрюле

c1 = (Q - c2m2(t2-t1)) / m1(t2 - t1)

c1 = (368730 - 4200*1*(100-15)) / 0.3*(100-15) = 460 Дж/(кг*С) - уд. теплоемкость железа

Ответ: кастрюля сделана из железа

Answer 2

Answer:

The material of the pot can be determined using the specific heat capacity formula, which is given by:

q = mcΔT

Where: - q = heat energy absorbed (in joules) - m = mass of the substance (in grams) - c = specific heat capacity of the substance (in J/g°C) - ΔT = change in temperature (in °C)

By rearranging the formula, we can solve for the specific heat capacity of the material:

c = q / (mΔT)

Given: - q = 368.73 kJ = 368730 J - m = 300 g - ΔT = (100°C - 15°C) = 85°C

Using the given values, we can calculate the specific heat capacity of the material and then identify the material based on its specific heat capacity.

Calculation:

c = q / (mΔT) c = 368730 J / (300 g * 85°C) c ≈ 15.77 J/g°C

Conclusion:

Based on the specific heat capacity calculated, the pot is likely made of aluminum. Aluminum has a specific heat capacity of approximately 0.897 J/g°C, which is close to the calculated value of 15.77 J/g°C [[1]].