Question

При равномерном подъёме груза массой 15 кг динамометр показывает 40Н . Длина наклонной плоскости 1,8 , а её высота 30 см . Вычислите КПД плоскости ( g =10 Н / кг ) . Помогите плиз кто хорошо ответит отмечу лучшим ответом .

Answer 1

Дано:m=15 кг
F=40Н
L=1.8 м
h=30см.Переведём в метры =0,3м
Найти К-?
Решение:Работа по перемещению груза А=F*L=40*1.8=72 Дж 
Полезная работa E=m*g*h=15*10*0,3=45 Дж (g=10 м/сек^2) 
К=(Е/А)*100%=(45/72)*100=62.5% 

Answer 2

Calculation of Efficiency (КПД) of the Inclined Plane

To calculate the efficiency (КПД) of the inclined plane, we need to use the formula:

КПД = (useful work output / total work input) * 100%

In this case, the useful work output is the force applied to lift the load, and the total work input is the force required to lift the load vertically.

Given: - Mass of the load (m) = 15 kg - Force measured by the dynamometer (F) = 40 N - Length of the inclined plane (l1) = 1.8 m - Height of the inclined plane (h) = 30 cm = 0.3 m - Acceleration due to gravity (g) = 10 N/kg

To calculate the useful work output, we need to find the force applied to lift the load vertically (F1).

Using the formula F = m * g, we can find F1: F1 = m * g = 15 kg * 10 N/kg = 150 N

Now, we can calculate the efficiency (КПД) using the formula mentioned above:

КПД = (F1 / F) * 100%

Substituting the values: КПД = (150 N / 40 N) * 100% = 375%

Therefore, the efficiency (КПД) of the inclined plane is 375%.

Please note that the given sources did not provide the exact formula for calculating efficiency, but the calculation method used here is based on the principles of work and energy.