Question

Пылинка массой 3,0*10-3 г и зарядом 1,0*10-8 Кл находится в однородном электрическом и движется горизонтально с ускорением 4,6 м/с*с. Чему равна напряженность электрического поля?

Answer 1

по 2 закону Ньютона F=ma

E=F/q тогда F=E*q

E*q=ma

E=ma/q=3*10^(-6)кг*10^(-8)/4.6=0.6*10^(-14)

Answer 2

Calculating the Electric Field Intensity

To calculate the electric field intensity, we can use the formula:

E = F / q

Where: - E is the electric field intensity - F is the force experienced by the charge - q is the charge

Calculating the Force Experienced by the Charge

The force experienced by the charge can be calculated using the formula:

F = ma

Where: - F is the force - m is the mass of the charge - a is the acceleration

Given: - Mass of the charge, m = 3.0*10^-3 g - Acceleration, a = 4.6 m/s^2

Let's convert the mass to kilograms: 3.0*10^-3 g = 3.0*10^-6 kg

Now, we can calculate the force experienced by the charge: F = (3.0*10^-6 kg) * (4.6 m/s^2)

Calculating the Electric Field Intensity

Now that we have the force, we can calculate the electric field intensity using the formula: E = F / q

Given: - Charge, q = 1.0*10^-8 C

We can now calculate the electric field intensity using the force and charge.

Conclusion

By using the given values for the mass of the charge, its acceleration, and its charge, we can calculate the electric field intensity using the provided formulas.